Q1. Attempt all sub-questions from Part A, Question 1.
- (a)) Calculate vrms for helium atoms at 300K. At what temperature will oxygen molecules have the same value of vrms? Take mнe = 6.67×10–27 kg. (200 words)
- (b)) What is most probable speed? Using the expression of the number of molecules in a Maxwellian gas in the range v to v + dv as dNv = 4πΝ (m/2πkBT)^3/2 v² exp (-mv²/2kBT) dv Obtain an expression for most probable speed. (200 words)
- (c)) Define mean free path? Obtain an expression of mean free path for zeroth order approximation. (200 words)
- (d)) What is Brownian motion? Write its two examples. Show that during sedimentation, particles concentration decreases exponentially as height increases. (200 words)
- (e)) Write the expressions of an ideal gas and van der Waals' equation. 10 moles of nitrogen gas occupy a volume of 5×10-3 m³ in a vessel at 27°C. Calculate the pressure exerted by the molecules, if it is assumed to obey van der Waals' equation. Compare this Value with that obtained using ideal gas law. Given: a = 1.39×10-6 atm m6 mol-2, b=39.1×10-6 m³ mol-1 and R = 8.2×10-5 atm m³ K-1mol-1. (200 words)
- vrms = √(3kBT/m); O₂ requires ~2390 K to match He's vrms at 300 K.
- Most probable speed (vmp) is peak of Maxwellian distribution; vmp = √(2kBT/m).
- Mean free path (λ) is average distance between collisions; Zeroth-order: λ = 1/(nπd²).
- Brownian motion is random particle movement due to molecular collisions; e.g., pollen in water, smoke in air.
Answer: Here are the comprehensive answers to all sub-questions from Part A, Question 1, adhering to the specified word limits and formatting requirements, drawing upon principles of Thermal Physics and Statistical Mechanics. ### (a) Root Mean Square Speed Calculation The root mean square speed (vrms) is a measure of the average speed of molecules in a gas, defined by the kinetic energy of the particles. It is given by the formula vrms = √(3kBT/m), where kB is the Boltzmann constant (1.38×10⁻²³ J/K), ...